IPV4 | Colocation America
This is an Internet Protocol (IPv4) Subnet Chart. You can use this to quickly look up how you might need to subnet your network. At the bottom there is a quick how-to on calculating subnets.
For more information on subnetting, see RFC 1817 and RFC 1812.
Class address ranges:
- Class A = 1.0.0.0 to 126.0.0.0
- Class B = 128.0.0.0 to 191.255.0.0
- Class C = 192.0.1.0 to 223.255.255.0
Reserved address ranges for private (non-routed) use (see RFC 1918):
- 10.0.0.0 -> 10.255.255.255
- 172.16.0.0 -> 172.31.255.255
- 192.168.0.0 -> 192.168.255.255
Other reserved addresses:
- 127.0.0.0 is reserved for loopback and IPC on the local host
- 224.0.0.0 -> 239.255.255.255 is reserved for multicast addresses
Chart notes:
- Number of Subnets - "( )" Refers to the number of effective subnets, since the use of subnet numbers of all 0s or all 1s is highly frowned upon and RFC non-compliant.
- Number of Hosts - Refers to the number of effective hosts, excluding the network and broadcast address.
Class A IP Addresses
| Network Bits | Subnet Mask | Number of Subnets | Number of Hosts |
| /8 | 255.0.0.0 | 0 | 16777214 |
| /9 | 255.128.0.0 | 2 (0) | 8388606 |
| /10 | 255.192.0.0 | 4 (2) | 4194302 |
| /11 | 255.224.0.0 | 8 (6) | 2097150 |
| /12 | 255.240.0.0 | 16 (14) | 1048574 |
| /13 | 255.248.0.0 | 32 (30) | 524286 |
| /14 | 255.252.0.0 | 64 (62) | 262142 |
| /15 | 255.254.0.0 | 128 (126) | 131070 |
| /16 | 255.255.0.0 | 256 (254) | 65534 |
| /17 | 255.255.128.0 | 512 (510) | 32766 |
| /18 | 255.255.192.0 | 1024 (1022) | 16382 |
| /19 | 255.255.224.0 | 2048 (2046) | 8190 |
| /20 | 255.255.240.0 | 4096 (4094) | 4094 |
| /21 | 255.255.248.0 | 8192 (8190) | 2046 |
| /22 | 255.255.252.0 | 16384 (16382) | 1022 |
| /23 | 255.255.254.0 | 32768 (32766) | 510 |
| /24 | 255.255.255.0 | 65536 (65534) | 254 |
| /25 | 255.255.255.128 | 131072 (131070) | 126 |
| /26 | 255.255.255.192 | 262144 (262142) | 62 |
| /27 | 255.255.255.224 | 524288 (524286) | 30 |
| /28 | 255.255.255.240 | 1048576 (1048574) | 14 |
| /29 | 255.255.255.248 | 2097152 (2097150) | 6 |
| /30 | 255.255.255.252 | 4194304 (4194302) | 2 |
Class B IP Addresses
| Network Bits | Subnet Mask | Number of Subnets | Number of Hosts |
| /16 | 255.255.0.0 | 0 | 65534 |
| /17 | 255.255.128.0 | 2 (0) | 32766 |
| /18 | 255.255.192.0 | 4 (2) | 16382 |
| /19 | 255.255.224.0 | 8 (6) | 8190 |
| /20 | 255.255.240.0 | 16 (14) | 4094 |
| /21 | 255.255.248.0 | 32 (30) | 2046 |
| /22 | 255.255.252.0 | 64 (62) | 1022 |
| /23 | 255.255.254.0 | 128 (126) | 510 |
| /24 | 255.255.255.0 | 256 (254) | 254 |
| /25 | 255.255.255.128 | 512 (510) | 126 |
| /26 | 255.255.255.192 | 1024 (1022) | 62 |
| /27 | 255.255.255.224 | 2048 (2046) | 30 |
| /28 | 255.255.255.240 | 4096 (4094) | 14 |
| /29 | 255.255.255.248 | 8192 (8190) | 6 |
| /30 | 255.255.255.252 | 16384 (16382) | 2 |
| Network Bits | Subnet Mask | Number of Subnets | Number of Hosts |
| /24 | 255.255.255.0 | 0 | 254 |
| /25 | 255.255.255.128 | 2 (0) | 126 |
| /26 | 255.255.255.192 | 4 (2) | 62 |
| /27 | 255.255.255.224 | 8 (6) | 30 |
| /28 | 255.255.255.240 | 16 (14) | 14 |
| /29 | 255.255.255.248 | 32 (30) | 6 |
| /30 | 255.255.255.252 | 64 (62) | 2 |
Supernetting (CIDR) Chart
- CIDR - Classless Inter-Domain Routing.
- Note: The Number of Class C networks must be contiguous.
For example, 192.169.1.0/22 represents the following block of addresses: 192.169.1.0, 192.169.2.0, 192.169.3.0 and 192.169.4.0.
Class C
| CIDR Block | Supernet Mask | Number of Class C Addresses | Number of Hosts |
| /14 | 255.252.0.0 | 1024 | 262144 |
| /15 | 255.254.0.0 | 512 | 131072 |
| /16 | 255.255.0.0 | 256 | 65536 |
| /17 | 255.255.128.0 | 128 | 32768 |
| /18 | 255.255.192.0 | 64 | 16384 |
| /19 | 255.255.224.0 | 32 | 8192 |
| /20 | 255.255.240.0 | 16 | 4096 |
| /21 | 255.255.248.0 | 8 | 2048 |
| /22 | 255.255.252.0 | 4 | 1024 |
| /23 | 255.255.254.0 | 2 | 512 |
| Quick Subnetting How-To (Thanks to Jason@ GeekVenue.) |
[Understanding decimal - Base 10] The decimal system has a 1's place, a 10's place, a 100's place, a 1000's place and so on. We say the number places are grouped by 10's because multiplying each number place by 10 gives you the next number place. So: 1x10=10 (the 10's place), 10x10=100 (the 100's place), 100x10=1000 (the 1000's place) etc. Let's look at the decimal number 103 by place. 103 <- read from right to left We have a 3 in the 1's place Thus: 100+0+3=103 By now you probably feel like you have attended Kindergarten for the second time in your life? Sorry about that but it is very important that you understand the concept of what a number system is, and what it is based on before we look at binary. [Understanding binary - base 2] Binary is a base 2 system, and thus groups numbers by 2's and not by 10's like the decimal system. We name the two digits: zero and one. The binary system has a 1's place, a 2's place, a 4's place, an 8's place, a 16's place and so on. We say the number places are grouped by 2's because multiplying each number place by 2 gives you the next number place. So: 1x2=2 (the 2's place), 2x2=4 (the 4's place), 4x2=8 (the 8's place), 8x2=16 (the 16's place) etc. Let's look at the decimal number Let's look at the decimal number 103 in binary format: 01100111 <- read from right to left We have a 1 in the 1's place Okay, Let's test your skills. Here is a list of binary numbers, try
converting them to decimal and check your answers at the end of this
post. [Understanding a subnet mask] The concept of a subnet mask is simple. You have a network and you have hosts on the network (anything with an IP address is a host). The subnet mask determines what portion of the TCP/IP address represents your network and what portion can be used for your hosts. Because I am a simple person, I think of it like this; The network number represents the street I live on, and the host portion is used for the numbers on all the houses on my street. A subnet mask of 255.255.255.0 means that the first three octets of the address will be used for the network, and thus our network number is 192.168.1. This means we can have 254 computers on this network, because the fourth octet is not being used by the network portion of the address. We know this because of the 0 in the subnet mask (255.255.255.0). We call each of the number sections an octet because we think of them in binary, and there are eight possible bits in each section. Eight bits is an octet. 11111111 in binary is 255 in decimal (did you do the conversions?). So our decimal subnet mask 255.255.255.0 displayed in binary is
going to be: If you count all the ones, you will find that there are 24 of them. Now look at the subnet mask examples again. Do you see why both subnet masks are the same? The number 24 is the number of bits used in the network portion of the address, and is short-hand for writing the address/subnet mask combination. It becomes important to understand this when you start dividing your network into multiple sub networks.
[Understanding Subnetting] Simply put, subnetting is dividing your network into multiple sub networks. To go back to my silly example about houses and streets, subnetting gives you multiple streets in your neighborhood. There are two methods for dividing your network into multiple sub networks; One is to simply change your network numbers keeping the same subnet mask. The other is to subnet your network into smaller sub networks. Keeping the same mask: Doing this would give you two separate networks with 254 hosts per network. This is a very common method of dealing with multiple networks. However, back in the good old days you had to pay for every IP address you used, and if you had 25 computers on your network you probably would not want to pay for 254 addresses! The answer to the problem is...subnetting. Subnetting a network: Lets look at a new subnet mask: As you can see in the fourth octet, some of the host portion of this subnet mask is now being used for part of the network address. Which means we are now using some of the binary bits in the fourth octet for our network numbers, and that gives us fewer hosts than our old mask (which gave us 254), but gives us more networks (which is why we call it subnetting). How can we tell how many networks and hosts per network this new subnet mask will give us? Well... we shall have to use some of our newly acquired binary skills. The first task is to find out how many bits in the fourth octet are being used? The decimal number is 224, what is the decimal number 224 as represented in binary? The decimal number 224 in binary is: We have a 0 in the 1's place Thus: 128+64+32+0+0+0+0+0=224 So our complete subnet mask in binary is: We now know that three bits from the fourth octet are used. How can we
tell how many sub networks we're going to have? This requires some
math- sorry. The formula is: 2n-2, where n is the number of bits being used from the host portion of our subnet mask. The formula for three bits is: In simpler terms: So our network is sub divided into 6 networks. Next, we want to know what the network numbers are, and how many hosts we can have on each of the 6 networks? What is the first subnet? Let's have a look at the bits in our fourth octet again. The bit that gives us the answer is the (1) closest to the first zero,
and in this case it is the 3rd bit from the left. The 3rd bit will start our first network, and the 3rd bit is in the 32's place (remember binary). Start adding the value 32 to itself six times to
get the six network numbers. Here are our network numbers: The host addresses will fall between the network numbers, so we will have 30 hosts per network. You're probably wondering why it's not 31? The answer is that the last address of each subnet is used as the broadcast address
for that subnet. Quiz: Subnet: 192.168.1.128 / 255.255.255.224 Let's look at another subnet mask: The answer is: So four bits are taken from the host portion of our mask. We do the same math as before: In simpler terms: We will have 14 sub networks, and what will the network numbers be? Look at the fourth bit, it's in the 16's place: Start adding 16 to itself- fourteen times to get all 14 network numbers: A better way to display our subnets is: The host addresses fall between the network numbers. So we will have 14 host addresses on each of our 14 sub networks (remember: the last or 15th address is the broadcast address for that subnet). If you had a small company with 10 hosts and needed to have a static IP address for all of your hosts, you would be assigned a network/subnet mask and a valid IP address range. Here is an example of what that might look like: [Answers to Binary Conversions] [Answer to Subnet Question] |





















